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Series

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Find the missing term in the series.
A1Z, E2V, I6R, M21N, Q88J, __

A)

F44SU


B)

U445F


C)

G342C


D)

V441G



Correct Answer :

U445F


Explanation :

A,(B,C,D)+3 =E
E,(F,G,H)+3 =I
I,(J,K,L)+3 =M
M,(N,O,P)+3 =Q
Q,(R,S,T)+3 =U

(1×1) + 1 = 2
(2×2) + 2 = 6
(6×3) + 3 = 21
(21×4)+ 4 = 88
(88×5)+ 5 = 445

Z,(Y,X,W)-3=V
V,(U,T,S)-3=R
R,(Q,P,O)-3=N
N,(M,L,K)-3=J
J,(I,H,G)-3=F

Hence , answer is U445F

Which of the following can replace the question mark?
N5V, K7T, ?, E14P, B19N

H9R
H10Q
H10R
I10R


Correct Answer :H10R

Which of the following can replace the question mark?
CD­12, LB­24, BP­32, NE­?

70
75
45
95


Correct Answer :70

Find the missing number in the series.
122, 213, 340, 509, 726, ?

A)
942

B)
997

C)
919

D)
950


Correct Answer :

997


Explanation :

The patteren is 5³ – 3 , 6³ – 3, 7³ – 3, 8³ – 3 , 9³ – 3, 10³ – 3,....
i.e, 5³ – 3 = 125 – 3 = 122
6³ – 3 = 216 – 3 = 213
7³ – 3 = 343 – 3 = 340
8³ – 3 = 512 – 3 = 509
9³ – 3 = 729 – 3 = 726
10³ – 3 = 1000 – 3 = 997
So, the missing number is 997.

Find the missing number in the series.
82, 107, 207, 432, 832, ?

A)
1550

B)
1450

C)
1457

D)
1542


Correct Answer :

1457


Explanation :

The patteren of the series
82 + (25 * 1² ) = 82 + 25 = 107
107+ (25 * 2²) = 107 + 100 = 207
207 + (25 * 3²) = 207 + 225 = 432
432 + (25 * 4²) = 432 + 400 = 832
832 + ( 25 * 5² ) = 832 + 625 = 1457
So, the missing number is 1457.

Find the missing number in the series.
4, 10, 28, 82, ?, 730

A)
224

B)
244

C)
242

D)
218


Correct Answer :

244


Explanation :

Each number in the series is 2 less than thrice the preceding number.
i.e, (4 * 3) – 2 = 12 – 2 = 10
(10 * 3) – 2 =30 – 2 = 28
( 28 * 3) – 2 = 84 – 2 = 82
( 82 * 3) – 2 = 246 – 2 = 244
( 244 * 3) – 2 = 732 – 2 = 730
So, the missing number is 244.

Find the missing number in the series.
1, 5, 13, ?, 41, 61

A)
25

B)
24

C)
26

D)
28


Correct Answer :

25


Explanation :

The pattern is + 4, + 8, + 12, + 16, ......
i.e, 1 +4 = 5
5 + 8 = 13
13 + 12 = 25
25 + 16 = 41
41 + 20 = 61
So, the missing number is 25.

Find the missing number in the series.
2, 3, 10, 15, ?

A)
25

B)
24

C)
26

D)
28


Correct Answer :

26


Explanation :

The pattern is
1² + 1 = 2
2² - 1 = 3
3² + 1 = 10
4² - 1 = 15
5² + 1 = 26.
So, the missing number is 26.

1000, 200, 40, … What number should come next?

A)
8

B)
10

C)
15

D)
20


Correct Answer :

8


Explanation :

This is a simple division series. Each number is divided by 5.

1000/5=>200
200/5=>40
40/5=>8

Find the missing number in the series.
2, 5, 3, 8, 5, 11, 6, ? , 9

A)
12

B)
13

C)
14

D)
15


Correct Answer :

15


Explanation :

2, 5, 3, 8, 5, 11, 6, ? , 9
2 + 3 = 5,
3 + 5 = 8,
5 + 6 = 11,
missing number = 6 + 9 = 15

What is the next term of this series
5, 7, 10, 15, 22, 33, 46 ,___, ___

A)
61,79

B)
63,82

C)
65,85

D)
59,71


Correct Answer :

63,82


Explanation :

The difference between the adjacent numbers itself form a series of consecutive prime numbers

5
5+2 = 7
7+3 = 10
10+5 =15
15+7 = 22
22+11 = 33
33+13 = 46
46+17 = 63
63+19 = 82

The missing number in 1,1,4,8,9,?,16,64 is:

A)
27

B)
23

C)
21

D)
20


Correct Answer :

27


Explanation :

the pattern of series 1=12, 1=13, 4=22 , 8=23, 9=32, 27=33, 16=42, 64=43

Find the missing alphabets in the following:
a_bc_a_bcda_ccd_bcd_

A)
abdbdb

B)
acbdbb

C)
adbbad

D)
bbbbbb


Correct Answer :

adbbad


Explanation :

The series is aabcd / abbcd / abccd / abcdd.
Thus, answer is adbbad

Find the missing number- 4, 196, 16, 169, ? , 144, 64

A)
81

B)
36

C)
32

D)
21


Correct Answer :

36


Explanation :

The odd terms
4*(1)2=4, 4*(2)2=16, 4*(3)2=36, 4*(4)2=64, 4*(5)2=100. …… so on
The even terms
(14)2=196, (13)2=169, (12)2=144, (11)2=121, (10)2=100, (9)2=81. .… so on

Find the missing term in the given series - 2,4,8,3,9,27,4,16,(?),5,25,125

A)
32

B)
64

C)
128

D)
156


Correct Answer :

64


Explanation :

pattern of series
2, 22, 23, 3, 32, 33, 4, 42, 43, 5, 52, 53

So missing term = 43 = 64

Find the missing term in the given series - 11A13, 17E19, (?), 31O37, 41U43

A)
21I23

B)
23I25

C)
25I27

D)
23I29


Correct Answer :

23I29

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