If the numerator of a fraction is increased by 150% and the denominator is increased by 300%,then the resultant fraction is 5/12 . What was the original fraction?
A)
2/3
B)
1/3
C)
3/5
D)
3/5
Your Answer : (Not Answered) Correct Answer :
2/3
Explanation :
Let the original fraction =x/y
New fraction =(250x/100)/(400y/100)=5/12
250x/400y =5/12
5x/8y=5/12
x/y =8/12 =>2/3
If 15 men take 21 days of 8 hours each to do a piece of work, then what is the number of days of 6 hours each that 21 women would take, if 3 women would do as much as 2 men?
The product of two numbers is 192 and the difference is 4. These two numbers are?
A)
16, 12
B)
18, 14
C)
17, 13
D)
15, 11
Your Answer : (Not Answered) Correct Answer :
16, 12
Explanation :
let the numbers are x and x-4
product of number is x*(x-4) =192
x2-4x-192=0
x2-4x-192=0
x2-16x+12x-192=0
(x-16)(x+12)=0
So x either 16 or -12 and other number either 12 or -16
that both sets of answers will work. (12 * 16) = 192 , (-12 * -16) = 192
A tradesman gives 4% discount on the marked price and gives an article free for buying every 15 articles and thus gains 35%.The marked price is above the cost price by?
A)
20.00%
B)
39.00%
C)
40.00%
D)
50.00%
Your Answer : (Not Answered) Correct Answer :
50.00%
Explanation :
Let the CP of each article be Rs 100
then CP of 16 articles=Rs (100*16)=Rs 1600
SP of 15 articles =1600*(135/100)=Rs 2160
SP of each article =2160/15=Rs 144
If SP is Rs 96, marked price =Rs 100
If SP is Rs 144,marked price =(100/96)*144= Rs 150
therefore marked price=(150-100) = 50% above CP
210 =1024.
unit digit of 210 * 210 * 210 is 4
as 4*4*4= 64 gives unit digit 4
unit digit of 231 is 4*2= 8.
Now 8 when divided by 5 gives 3 as remainder.
231 when divided by 5 gives 3 as remainder.
What is cos4 A - sin4 A / cos2 A - sin2 A equal to?
A)
cos2 A - sin2 A
B)
cos A - sin A
C)
1
D)
2
Your Answer : (Not Answered) Correct Answer :
1
Explanation :
cos4 A - sin4 A / cos2 A - sin2 A
= (cos2 A)2 - (sin2A)2 / cos2 A - sin2 A
= (cos2 A + sin2A) (cos2 A - sin2A) / (cos2 A - sin2 A)
= (cos2 A + sin2A) (cos2 A - sin2A) / (cos2 A - sin2 A)
= (cos2 A + sin2A)
= 1
By using digits 1 to 9 how many 4 digit numbers can be formed which has 5 as a unit digit? Repetition of digits is are not allowed.
A)
336
B)
1400
C)
504
D)
251
Your Answer : (Not Answered) Correct Answer :
336
Explanation :
5 at the unit place or divisible by 5. So, there is 1 way of doing it.
No repetition of digits.thus there are 8 ways of filling the tens place from the remaining 8 digits (1,2,3,4,6,7,8,9).
the hundreds place can be filled by any of the remaining 7 digits. So, there are 7 ways of filling it.
the thousands place can be filled by any of the remaining 6 digits. So, there are 6 ways of filling it.
Required number of numbers = (1 * 8 * 7 * 6) = 336.
A passenger train departs from Delhi at 6 p.m. for Mumbai. At 9 p.m. an express train, whose average speed exceeds that of the passenger train by 15 km / hour leaves Mumbai for Delhi. Two trains meet each other mid-route. At what time do they meet, given that the distance between the cities is 1080 km?
A)
4 p.m.
B)
2 a.m.
C)
12 mid-night
D)
6 a.m.
Your Answer : (Not Answered) Correct Answer :
6 a.m.
Explanation :
Let the speed of passenger train= x km/hr
Speed of express train = (x + 15) km/hr
Then, As is given
The sum of all possible two digit numbers formed from three different one digit natural numbers when divided by the sum of the original three numbers is equal to?
A)
18
B)
22
C)
36
D)
45
Your Answer : (Not Answered) Correct Answer :
22
Explanation :
Let the one digit numbers x,y,z
Sum of all possible two digit numbers
=>(10x+y)+(10x+z)+(10y+x)+(10y+z)+(10z+x)+(10z+y) = 22(x+y+z)
Therefore sum of all possible two digit numbers when divided by sum of one digit numbers gives 22.
An express train runs 900 km at an average speed of 90 km/hour, stopping for 3 minutes at stations after every 100 km. How long it would take to reach its destination?
A)
10 hr 30 min
B)
10 hr 24 min
C)
10 hr 27 min
D)
10 hr
Your Answer : (Not Answered) Correct Answer :
10 hr 24 min
Explanation :
Time taken by express train to cover 900 km = 900/90 = 10 hr
Time taken during stoppage= train stop 8 times in the whole journey after every 100 km= 8 *3 = 24 min.
So, total time taken by train including stoppage= 10 hr 24 min.
Ravi invested amount P in a scheme A offering simple interest at 10% per annum for two years. He invested the whole amount he received from scheme A, in another scheme B offering simple interest at 12% per annum for five years. If the difference between the interests earned from schemes A and B was 1300, what is the value of P?
A)
2500
B)
2000
C)
3000
D)
3500
Your Answer : (Not Answered) Correct Answer :
2500
Explanation :
SI from scheme A = P*10*2 /100 =P/5
Amount received from scheme A =P + P/5 = 6P/5
Now, SI from scheme B= (6P/2)*12*5 /100 = 18P/25
According to the question, 18P/25 - P/5 = 1300
13P/25=1300
P=2500
