In an election to a municipal council, the votes secured by two candidates are in the ratio 13:19. The elected candidates gets 312 votes more than the second candidate. How many votes are secured by the second candidate?

A)

500

B)

620

C)

676

D)

700

Your Answer : (Not Answered) Correct Answer :

676

Explanation :

Let the two candidates are A and B
the ratio is 13:19
So,
A's votes = 13x
B's votes = 19x

As is given
19X - 13X = 312
6X = 312
X = 52
Hence A's votes= 13X = 13*52 =676
and B's votes= 19X = 19*52 = 988

In a rhombus of side 10 cm, one of diagonals is 16 cm long. The length of In a rhombus of side 10 cm, one of diagonals is 16 cm long. The length of the second diagonal is ?

A)

16 cm

B)

12 cm

C)

18 cm

D)

20 cm

Your Answer : (Not Answered) Correct Answer :

12 cm

Explanation :

The diagonals meet in the middle at a right angle.
All sides of rhombus are equal i.e. 10cm
(Side)^{2}=(half of one diagonal)^{2}+(half of second diagonal)^{2}
by using this formula
(10)^{2}=(8)^{2}+(half of second diagonal)^{2}
(half of second diagonal)^{2} = 36
half of second diagonal=6
second diagonal=12cm

Rs. 1900 is divide between A, B and C so that A's share is 1*(1/2) times B's and B's is 1*(1/2) times C’s. What C’s share?

A)

Rs.800

B)

Rs.420

C)

Rs.400

D)

Rs.900

Your Answer : (Not Answered) Correct Answer :

Rs.400

Explanation :

Let C = x,
Then B = (3/2)* x and A = (3/2)*(3/2)* x = (9/4) * x
A : B : C = (9/4) * x : (3/2)* x : x = 9 : 6 : 4
So, C's capital = Rs. (1900×4/19)
= Rs. 400

A and B together can do a work in 8 days. If A alone can do it in 12 days, then in how many days can B alone do it?

A)

12 days

B)

20 days

C)

24 days

D)

28 days

Your Answer : (Not Answered) Correct Answer :

24 days

Explanation :

If X can do a piece of work in n days, then X's 1 day's work =1/n
If A and B, working together,and can complete a piece of work in X days. If A, working alone, can
complete the work in Y days, then B working alone, will complete the work in XY/(Y-X) days.

Then ,B alone can complete = (12 * 8) / (12 - 8) = 96/4 = 24 days

One year ago the ratio of Ramu & Somu age was 6:7 respectively. Four years hence their ratio would become 7:8. How old is Somu?

A)

32

B)

34

C)

36

D)

38

Your Answer : (Not Answered) Correct Answer :

36

Explanation :

Let us assume Ramu & Somu ages, 1 year ago, be 6x and 7x respectively.
Given that, four years hence, this ratio would become 7:8
⇒(6x+5):(7x+5)=7:8
⇒8(6x+5)=7(7x+5)
⇒48x+40=49x+35
⇒x=5
Somu's present age = 7x+1= 7×5+1=36 years

In a cricket test series, the runs made by Raju and Tendulkar are in the ratio 5:9 and Tendulkar and Azar are in the ratio 6:7. What are the runs made by them if Azar makes 187 runs more than Raju?

A)

110,126,250

B)

120,216,307

C)

170,306,357

D)

168,206,352

Your Answer : (Not Answered) Correct Answer :

170,306,357

Explanation :

The ratio is
R/T = 5/9 = 5*6/9*6
T/A = 6/7 = 6*9/7*9

So, rotio of their runs
R:T:A = 5*6:9*6:7*9
= 5*2:9*2:7*3
= 10:18:21

PQRS is the greatest number of 4 digits which when divided by any of the numbers 6, 9, 12 or 17 leaves a remainder of 2 in each case. What is the value of (P + R)/(Q + S)?

A)

18

B)

18/11

C)

11/18

D)

9/11

Your Answer : (Not Answered) Correct Answer :

18/11

Explanation :

The required number, which is exactly divisible by each one of the given numbers, should be divisible by LCM of (6, 9, 12, 17) i.e. 612
The Largest number of four digits is 9999.by dividing 9999 to 612 get 207 as remainder.
So, the greatest number of 4 digits divisible by any numbers from 6, 9, 12 or 17 = (9999-207) = 9792.

But we should get the remainder as 2,so we need to add 2 to 9792.So the number PQRS is 9794.

In a 100 race,A can give B 10 m and C 28 m.In the same race B can give C?

A)

14 m

B)

18 m

C)

20 m

D)

36 m

Your Answer : (Not Answered) Correct Answer :

20 m

Explanation :

Ratio of speeds of A:B =100 :90
Ratio of speeds of A :C=100 :72
Ratio of speeds of B:C =B/A *A/C
=90/100*100/72 =90/72
When B runs 90 C runs 72
when B runs 100 C runs =72*100/90 = 80 m
So, B beats C by (100-80)= 20m

A copper wire when bent in the form of a square encloses an area of 121 cm^{2}. If the same wire is bent in the form of a circle, it encloses an area equal to?

A)

121 cm^{2}

B)

144 cm^{2 }

C)

154 cm^{2}

D)

168 cm^{2}

Your Answer : (Not Answered) Correct Answer :

154 cm^{2}

Explanation :

As is given, area of square = a^{2} = 121 cm^{2}
So, side of square, a = 11 cm

length of the wire = Perimeter of square of side a = 4a = 4*11 = 44cm

Let the radius of circle be r cm. Then,
Perimeter of circle = Length of wire
=> 2πr = 44 cm
=> r = 44/2π = 7 (π = 22/7)

Now, Area of circle = πr^{2} = (22/7) *7*7 = 154 cm^{2}