Alligation or Mixture - Aptitude Questions and Answers

View in English View in Hindi

How much water is to be mixed in 20 liters of 20% sugar solution so that the resultant solution contains 8% sugar?

A)
10 liter

B)
20 liter

C)
24 liter

D)
30 liter


Correct Answer :

30 liter


Explanation :

Initial Solution = 20 liters(water+sugar)
Initial sugar=20%
So, Initial Water=80% of 20 = 16

Let x is the water to be added to the mixture so that the new mixture must have ontains 8% sugar i.e. 92% water

Thus,new Solution = 20+x
water in new Solution = 16+x

16+x = 92% of (20+x)
16+x = (92/100)*(20+x)
16+x = (23/25)*(20+x)

400+25x=460+23x
2x = 60
x = 30 L

Post comment
Cancel
Thanks for your comment.!
Write a comment(Click here) ...
View in English View in Hindi

In what ratio should water be mixed with wine that costs Rs. 60 per litre so that after selling the resultant mixture at Rs.50 per litre, the profit will be 25%?

A)
1 : 2

B)
2 : 3

C)
3 : 4

D)
4 : 5


Correct Answer :

1: 2


Explanation :

Let X is the cost of pure wine. Then,
Cost of resultant mixture, X + 25% of X = 50
100X + 25X = 50*100
125X = 50 *100
X = 5000/125 = Rs. 40

So, wine of Rs. 40(CP) sold at Rs. 50(SP)

Now, in Rs. 60 = 1 litre wine.
So, in Rs.40 = 40/60 = 2/3 part wine, remaining part 1/3 water.
Therefore ratio Water : Wine = 1/3 : 2/3
= 1:2

In what ratio should water be mixed with wine, that costs Rs.60 per litre, so that the price of the resultant mixture is Rs.40 per litre?

A)
2 : 3

B)
4 : 5

C)
3 : 4

D)
1 : 2


Correct Answer :

1 : 2


Explanation :

By the rule of alligation: If two ingredients are mixed, then
Quantity of cheaper/Quantity of dearer =[(C.P. of dearer) - (Mean price)] / (Mean price) - [(C.P. of cheaper)]

i.e. (Cheaper Quantity):(Dearer quantity)= (d-m):(m-c).

C.P. of cheaper(in paise) ,Water c=0/lit
C.P. of dearer(in paise),Wine d=60/lit
Mean price(in paise) or resultant mixture costs, m= 40/lit

Thus ,(Cheaper Quantity):(Dearer quantity)= (60-40) / (40- 0)
=> 20:40 =>1:2

16 litres of kerosene is mixed with 5 litres of petrol. The price of kerosene is Rs. 12 per litre and price of petrol is Rs. 33 per litre. The average price of the resultant mixture per litre is?

A)
15 rs

B)
17 rs

C)
21 rs

D)
23 rs


Correct Answer :

17 rs


Explanation :

Average price of the resultant mixture= (16×12+5×33) / (16+5)
=357 / 21
=17

There is 10% water in 100 liters mixture of milk and water. How much more water is to be added to the mixture so that the resultant solution contains 25% water?

A)
15 litre

B)
20 litre

C)
10 litre

D)
None of these


Correct Answer :

20 litre


Explanation :

There is 10% water in 100 liters mixture of milk and water. How much more water is to be added to the mixture so that the resultant solution contains 25% water?

Initial Solution = 100
Initial water =10% of 100 = 10

Let x is the water to be added to the mixture so that the new mixture must have 25% water

new Solution = 100+x
water in new Solution = 10+x

10+x = 25% of (100+x)
10+x = (25/100)*(100+x)
10+x = (1/4)*(100+x)
40+4x=100+x
3x = 60
x = 20 L

In what ratio should the wheat that costs Rs.7.50 per kg, be mixed with the wheat that costs Rs.11 per kg so that the resultant mixture costs Rs.8.25 per kg?

A)
8 : 5

B)
9 : 7

C)
11 : 3

D)
10 : 3


Correct Answer :

11 : 3


Explanation :

By the rule of alligation: If two ingredients are mixed, then
Quantity of cheaper/Quantity of dearer =[(C.P. of dearer) - (Mean price)] / (Mean price) - [(C.P. of cheaper)]

i.e. (Cheaper Quantity):(Dearer quantity)= (d-m):(m-c).

C.P. of cheaper(in paise) , c=750
C.P. of dearer(in paise), d=1100
Mean price(in paise) or resultant mixture costs, m= 825

Thus ,(Cheaper Quantity):(Dearer quantity)= (1100-825) / (825- 750)
= (1100-825) / (825- 750)
=275 / 75
=11 / 3

In 1 litre mixture of sprit and water, 20% is water. How much sprit should be added, so that the proportion of water becomes 5%?

A)
3 litres

B)
4 litres

C)
5 litres

D)
6 litres


Correct Answer :

3 litres

There are two types of mixture of milk and water. In the first mixture, out of 27 ltr, 24 ltr is milk only and in the second mixture, 40 ltr is milk and 5 ltr is water. Which one mixture is better in terms of milk’s strength?

A)
First

B)
Second

C)
Same in both

D)
Data insufficient


Correct Answer :

Same in both

An ore contains 25% of an alloy that has 90% copper. Other than this, in the remaining 75% of the ore, there is no copper. How many kilograms of the ore are needed to obtain 60 kg of pure copper?

A)
250

B)
275

C)
300

D)
266.66


Correct Answer :

266.66


Explanation :

Let there is 100 kg ore.
25% of ore contains 90% copper,which means 25 kg contains; 25*90/100 = 22.5 kg of copper.

22.5 kg copper included in 100 kg of ore.
Then, 1 kg of copper = 25/100 kg ore contains
Hence, 60 kg copper = 100*60/22.5 = 266.66 kg of ore contains

The ratio of two liquids in a mixture is 3 : 5 and that in another mixture is 6:1. In what ratio these two mixtures must be mixed so as to make the ratio of the two liquids 7:3?

A)
44 : 61

B)
44 : 71

C)
44 : 81

D)
44 : 91


Correct Answer :

44 : 91


Explanation :

By the rule of alligation: If two ingredients are mixed, then
Quantity of cheaper/Quantity of dearer =[(C.P. of dearer) - (Mean price)] / (Mean price) - [(C.P. of cheaper)]

i.e. (Cheaper Quantity):(Dearer quantity)= (d-m):(m-c).

ratio of a liquid1 in mixture1, c=3/8
ratio of a liquid1 in mixture2, d=6/7
Mean ratio of a liquid1 or ratio of a liquid1 in resultant mixture, m= 7/10

Thus ,Required ratio = (6/7 - 7/10) / (7/10 - 3/8)
= ((60-49)/70) / ((28-15)/40)
=(11/70) / (13/40)
=(11*40) / (70*13)
=44 / 91

A mixture of 40 litres of milk and water contains 10% water. How much water should be added so that the water is 20% in the new mixture?

A)
4 L

B)
7 L

C)
5 L

D)
8 L


Correct Answer :

5 L


Explanation :

Initial Solution = 40
Initial water =10% of 40 = 4

Let x water be added then the new mixture must have 20% water

Final Solution = 40+x
Final water = 4+x

4+x = 20% of (40+x )
4+x = (20/100)*(40+x )
4+x = (1/5)*(40+x )
20+5x=40+x
4x=20
x = 5
water to be added to the mixture, x = 5

In Jar A, 180 L milk was mix with 36 L water.Some of this mixture was taken out from Jar A and put it in Jar B. If after adding 6 L of water in the mixture, the respective ratio between milk and water in Jar B was 5 : 2 respectively, what was the amount of mixture that was taken out from Jar A?

A)

24


B)

54


C)

30


D)

36



Correct Answer :

36


Explanation :

Ratio of milk and water in jar A = 180 L : 36 L = 5 : 1
Let, x L of mixture taken out from jar A.

So, Quantity of milk taken out from jar A = x*5/6 = 5x/6
and Quantity of water taken out from jar A = x*1/6 = x/6

Now, according to the question,
(5x/6) / (x/6 + 6) = 5/2
(5x/6) / (x + 36)/6 = 5/2
5x / (x + 36) = 5/2
10x = 5x + 180
5x = 180
x = 36
Hence, 36 L of mixture was taken out from Jar A.

25 kg of alloy X is mixed with 125 kg of alloy Y. If the amount of lead and tin in the alloy X is the ratio 1 : 2 and the amount of lead and tin in the alloy Y is in the ratio 2 : 3, then what is the ratio of lead to tin in the mixture?

A)
1 : 2

B)
2 : 3

C)
3 : 5

D)
7 : 11


Correct Answer :

7 : 11


Explanation :

Alloy X
Total 25
Ratio 1:2
lead 25* (1/3)=25/3
tin 25* (2/3)=50/3

Alloy Y
Total 125
Ratio 2:3
lead 125* (2/5)=50
tin 125* (3/5)=75

When X and Y are mixed, then
Amount of lead = (25/3) + 50 = 175/3 kg
Amount of tin = (50/3) + 75 = 275/3 kg

Ratio of lead to tin in the mixture = (175/3) / (275/3) = 175 : 275 = 7 : 11

In what ratio must Rs 50 per kg salt be mixed with Rs 80 per kg salt to obtain a mixture worth of Rs 60 per kg?

A)

1 : 2


B)

2 : 1


C)

1 : 1


D)

3 : 2



Correct Answer :

2 : 1


Explanation :

The Required ratio = cp of biggest - mean price / mean price- cp of lowest
=(80 – 60)/(60- 50)
=20:10
=2:1

Latest Updates

Fractions

First we increased the denominator of a positive fraction by 3 and then decrease it by 5.The sum of the resulting fractions proves to be equal to 2/3. Find the denominator of the fraction if its numerator is 2?

Simplification

If we divide a two digit number by the sum of its digits we get 4 as a quotient and 3 as a remainder. Now if we divide that two digit number by the product of its digits we get 3 as a quotient and 5 as a remainder . Find the two digit number?

Fractions

The denominators of an irreducible fraction is greater than the numerator by 2.If we reduce the numerator of the reciprocal fraction by 3 and subtract the given fraction from the resulting one,we get 1/15.Find the given fraction?

Simplification

If we add the square of the digit in the tens place of the positive two digit number to the product of the digits of that number we get 52,and if we add the square of the digit in the unit's place to the same product of the digits we get 117.Find the two digit number?

The sum of squares of the digits constituting a positive two digit number is 13, If we subtract 9 from that number we shall get a number written by the same digits in the reverse order. Find the number?

The arithmetic mean of two numbers is smaller by 24 than the larger of the two numbers and the GM of the same numbers exceeds by 12 the smaller of the numbers. Find the numbers?

A number being successively divided by 3,5,8 leaves remainder 1,4,7 respectively. Find the respective remainders if the order of divisors are reversed?

The sum of all possible two digit numbers formed from three different one digit natural numbers when divided by the sum of the original three numbers is equal to?

HCF and LCM

Find the HCF and LCM of the polynomial x2-5x+6 and x2-7x+10?

Simplification

When we multiply a certain two digit number by the sum of its digits , 405 is achieved. If we multiply the number written in reverse order of the same digits by the sum of the digits, we get 486. Find the number?

Average

The sum of two numbers is 15 and their geometric mean is 20% lower than their arithmetic mean. Find the numbers?

Numbers

The difference of 1025-7 and 1024+x is divisible by 3. find x=?

A number when divided by the sum of 555 and 445 gives two times their difference as quotient and 30 as remainder . The number is?

The sum of three prime numbers is 100.If one of them exceeds another by 36 then one of the numbers is?

Find the number of zeros in the factorial of the number 18?

If a number is multiplied by 22 and the same number is added to it then we get a number that is half the square of that number. Find the number?

In doing a division of a question with zero remainder,a candidate took 12 as divisor instead of 21.The quotient obtained by him was 35. The correct quotient is?

Fractions

A number when divided by 342 gives a remainder 47.When the same number is divided by 19 what would be the remainder?

Latest Job Notifications

Jobs in West Bengal

इंडियन पोस्ट सर्विस Indian Post Service - 2357 पद - 19/08/2021 अंतिम तिथि - पश्चिम बंगाल पोस्टल सर्कल

Banking Jobs

भारतीय स्टेट बैंक State Bank of India(SBI) - 6100 पद - 26/07/2021 अंतिम तिथि - CRPD/APPR/2021-22/10

SSC Recruitment

कर्मचारी चयन आयोग Staff Selection Commission(SSC) - 25271 पद - 31/08/2021 अंतिम तिथि

Jobs in Madhya Pradesh

राष्ट्रीय स्वास्थ्य मिशन मध्य प्रदेश National Health Mission MP(NRHM) - 5215 पद - 22/06/2021 अंतिम तिथि

Jobs in Punjab

पंजाब स्टेट पावर कॉर्पोरेशन लिमिटेड Punjab State Power Corporation Limited (PSPCL) - 2632 पद - 20/06/2021 अंतिम तिथि

Jobs in Chhattisgarh

स्वास्थ्य सेवा निदेशालय, छत्तीसगढ़ Department of Health & Family Welfare, Chhattisgarh - 267 पद - 26/06/2021 अंतिम तिथि

Government Jobs

दिल्ली सबऑर्डिनेट सर्विस सिलेक्शन बोर्ड Delhi Subordinate Services Selection Board(DSSSB) - 5807 पद - 03/07/2021 अंतिम तिथि

Jobs in Madhya Pradesh

राष्ट्रीय स्वास्थ्य मिशन मध्य प्रदेश National Health Mission MP(NRHM) - 2850 पद - 31/05/2021 अंतिम तिथि

Government Jobs

इंडियन पोस्ट सर्विस Indian Post Service - 4368 पद - 29/05/2021 अंतिम तिथि

दिल्ली सबऑर्डिनेट सर्विस सिलेक्शन बोर्ड Delhi Subordinate Services Selection Board(DSSSB) - 7236 पद - 24/06/2021 अंतिम तिथि