Problems on Ages- Aptitude Questions and Answers

Let the present age of Raju is x,then after 15 years
x+15 = 5(x-5)
x + 15 = 5x – 25
5x – x = 25 + 15
4x = 40
x = 40 / 4
x = 10

total age of 16 professors => 52 years * 16 professors => 832 years
after 4 years total age would be 832 years (16professors * 4 years)= 896 years

Then Average age would be After four years => 896/16 => 56 years

As given three years ago, Xs age was 2 times as that of Ys then (x-3) = 2(y-3)
x = 2y-3 ------------------eq1
The sum of their ages will be 83 years, then (x+7) + (y+7) = 83
x+y = 69------------------eq2

After substitute the value of x from eq1 to eq2.
(2y-3) + y = 69
3y - 3 = 69
3y = 72
y = 24

If y is 24, then substitute the value of y in eq2
x+y = 69
x=69-24
x=45

Total age of 5 members, 10 years ago = (25 * 5) years = 125 years

Total age of 5 members now = (125 + 10 * 5) years = 175 years

Total age of 7 members now = (27 * 7) years = 189 years

Sum of the ages of 2 children = (189 - 175) years = 14 years

Let the age of the younger child be x years.

Then, age of the elder child = (x + 4) years

So, x + x + 4 = 14 <=> 2x = 10 <=> x=5

Hence, Age of younger child = 5 years,
And age of the elder child = (x + 4) years=>(5 + 4) years=>9 years

sum of 5 members ages 3 years ago = 5 * 27 = 135
in present sum of 5 members ages = 135 + 5*3 = 150

let age of child is x
Sum of 6 members ages now:
150 + x = 6 * 27
150 + x = 162
age of child x = 12

let the present ages of Ruhi, Richa and Reema are X ,Y and Z
and as per question X+Y+Z=60 years

then 3 years ago total ages of them is X-3+Y-3+Z-3=(X+Y+Z)-9=60-9=51 years

At present the total age of the family = 5 * 21 = 105
The age of the youngest member be 5 years
The total age of the remaing family member during 5 year 4*5=20 after birth of youngest member

The total age of the family at the time of the birth of the youngest member that is 5 year ago => present the total age of the family -age of the youngest member- change in total age of the remaing family member during 5 year
=> 105-5-20 = 80

Therefore, average age of the family at the time of birth of the youngest member =>total age of the family at the time of the birth of the youngest member / number of member in family at the time of birth of the youngest member
=>80/4 = 20

Let , the present age of father is f and age of son is s
10 years ago ratio of their ages, (f-10)/(s-10)=3/1
f-10=3s-30=>f-3s=-20
f=3s-20

10 years after ratio of their ages, (f+10)/(s+10)=5/3
3f+30=5s+50
3f-5s=20
substitute value of f here
3(3s-20)-5s=20
9s-60-5s=20
4s=80
s=20

if s=20 then f=3s-20=60-20=40
Hence f = 40, s = 20, ratio of son to father age is s/f=20/40 =1/2

Let the son's present age be x years then , (x + 4) + (4x + 4) = 43
5x = 35
Thus, x = 7

Suppose x years later the father will be twice as old as his son.
Then, x + 41 = 2 (x + 16)
⇒ x = 41 - 32 = 9 years

Hence the father be twice as old as his son in 9 years

Let the present of Meena and Seema are 7k yr and 8k yr, respectively.
Then, 8k - 7k = 3
k = 3

Hence, required sum = 8k + 7k = 15k = 15 * 3 => 45 yr

Let age of Rohan be y
Ajay is 15 years elder than Rohan,So Ajay’s age = (y + 15).
5 years ago, Ajay is 3 times as old as Rohan
(y + 15 – 5) = 3 (y – 5)
(y + 10) = (3y – 15)
2y = 25
y = 12.5
Rohan's age = 12.5 years
Ajay's age = (y + 15) = (12.5 + 15) = 27.5 years

Let one year ago, Harry’s age = 5x and Ram's age = 6x
Hence at present, Harry’s age = 5x +1 and Ram’s age = 6x +1
After 4 years, this ratio becomes 6 : 7.
Therefore, Harry’s Age / 6 = Peter’s Age / 7
=>((5x +1) + 4) / ((6x +1) + 4) = 6 / 7
7 (5x + 5) = 6 (6x + 5)
35 x + 35 = 36x + 30
36x – 35x = 35 – 30
x = 5
Ram’s present age = (6x + 1)
= (6 * 5) + 1
= 31 years

Let Ajay age is x, then Sachin age is x-7,
So, Sachin’s Age / Ajay ’s Age => (x-7)/x = 7/9
9(x – 7) = 7x
9x-63 = 7x
9x – 7x = 63
2x = 63
x = 31.5
So Sachin age is, x-7 => 31.5 - 7 = 24.5

Let P age and Q age is 6x years and 7x years.
As given, 7x - 6x = 4
x = 4
So required ratio will be (6x+4)/ (7x+4)
=> 28 / 32
=> 7/8

Let,the present age Madhu is 2x and Puja is 6x
After 5 years,the ratio of their ages, (2x+5)/(6x+5)=3/4
8x+20=18x+15
10x=5
x=1/2
So,the present age Madhu is 1 year and Puja is 3 year
The average of their ages after 10 years is {(1+10)+(3+10)}/2
=24/2
=12

Let son’s age be x years. Then, father’s age = (3x) years.
Five years ago, father’s age = (3x – 5) years and son’s age = (x – 5) years.

As given, Five years back, father’s age was four times
So, 3x – 5 = 4 (x – 5)
3x – 5 = 4x – 20
x= 15.