Profit and Loss- Aptitude Questions and Answers

6% of cost price (CP) = 1425 - 1353 = 72
Thus, CP = ( 72 * 100 ) / 6 = 1200

Profit = SP - CP
Profit% = (Profit* 100)/CP

Let SP of 1 banana is x.
Then , SP of 8 bananas = 8x.
Gain=selling price of 1 banana= 1x.
CP = SP-gain=7x

Therefore %Gain = (1x*100)/7x
profit%= 14.28~%.

Profit = SP - CP
Profit% = (Profit* 100)/CP

Let SP of 1 meter cloth is x.
Then , SP of 27 meter cloth = 27x.
Gain=SP of 9 meter cloth = 9x.
CP = SP-gain=27x-9x=18x

Therefore %Gain = (9x*100)/18x
profit%= 50%.

Let the CPs of car is Rs.100
1st SP on profit of 10% = 100 + 10% * 100 = Rs.110.
2nd SP on loss of 20% = 100 - 20% * 100 = Rs.80.
Total CP of both car = Rs.200.
Total SP of both car = (110+80)= Rs.190

Loss = CP - SP = 200-190 = Rs.10
Loss%= (Loss * 100)/CP= (10*100)/200 = 5
So, 5% Loss

Let, Original CP of 1000g = Rs. 1000
New CP,after 10% above= 1000 + 10 % of 100=> Rs.1100

Trader cheats his customer by giving 880g only instead of 1kg,
So, CP of 880g should be= Rs. 880
SP of 880g =CP of 1 kg+ 10% above of 1kg CP= 1000 + 100 =1100

Profit% = ((SP - CP)* 100)/CP
Profit % = [ ( 1100 - 880 ) / 880 ] * 100
Profit % = [ 220 / 880 ] * 100
Profit % = 25

Remaining eggs = 200 - 38 = 162
The rate of 4.80 per dozen, therefore selling price of 168 eggs, SP= 162 * (4.8/12) => 64.8

Profit% = ((SP - CP)* 100)/CP
8 = ((64.8 - CP)* 100)/CP
8*CP=6480-100*CP
108*CP=6480
CP=6720/108
CP=60

Profit = SP - CP (if SP > CP),
Each dozen carries cost 75 rupees and are sold for 12 x 15 = 180 rupees
Profit = 180-75 = 105 rupees

As given, 10 % x = 15% of y , then, x / y = 3/2 -------(1)
Total sale price of these two articles= x+y = 30000 -------(2)
By solving eq. (1) & (2) , x = 18000, y = 12000

Hence, the difference, (x-y)=6000

Let cost price be X , Selling price = 2345 and loss = 19%
Cost price, X = (SP * 100)/(100 - Loss%)
= (2345 * 100)/(100 - 19%)
X = 234500/81 = 2895 ≈ 3000

Let the CP be Rs. x , then SP be 0.96x
Then, 0.96x = 240
⇒ x = 250

Now the new SP = 250 X 1.1 = 275

Let x be the cost price of the horse and y be the cost price of the cart.
In the first sale there is no loss or profit. (i.e.) The loss obtained is equal to the gain.
Therefore (10/100) * x = (20/100) * y
x = 2 * y -----------------(1)
In the second sale, he lost Rs. 10. (i.e.) The loss is greater than the profit by Rs. 10.Therefore
(5 / 100) * x = (5 / 100) * y + 10 -------(2)
Substituting (1) in (2) we get
(10 / 100) * y = (5 / 100) * y + 10
(5 / 100) * y = 10

y =cost price of the cart = 200
From (1) x= 2 * 200 =cost price of the horse = 400

Profit = SP - CP (i.e., if SP > CP)
As given, CP = 60% of SP => (60/100) *SP

Thus,
60 = SP - (60/100) *SP
60 = SP*(40/100)
SP=(60*100)/40
the selling price is SP=150

Profit = SP - CP ( if SP > CP)
Profit% = (Profit* 100)/CP

Let the cost price is Rs 100,Thus the selling price with 10% loss = Rs 90
that is, Rs 90 =3/5 of the original selling price

So the original selling price = 90 * 5/3 = Rs 150
Thus,gain = 150 -100 = 50
Gain% = (50*100)/100 => 50%

C.P of 1 apples = 100/11
S.P of 1 apples = 110/10
Profit = S.P - C.P
=11-(100/11)
=(121-100)/11
=21/11

Profit% = (Profit/C.P)*100
=((21/11)/(100/11))*100
= 21%

Selling price of watch, SP = 4950, Loss = 10%
SP = CP*(100 - Loss%)/100
Thus, 4950 = CP*(100 - 10)/100
CP = (4950 * 100) / 90
= 495000/90
cost price of the watch, CP = 5500

80 : 9 = 105 : x
x = (9×105/80)
= Rs.11.81
Hence, SP per Kg= Rs.11.81

CP = 180,Gain = 20%
SP = (120/100) * 180= 216

Let the Marked Price be x.
Then, 80% of x = 216
80x/100 = 216
x =216*100/80 =217

Thus, Marked Price is 270