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In 30 km distance, Abhay takes two hours more than Sameer. If Abhay will double his speed, then he will take less than 1 hour from Sameer. What is the speed of Abhay (in km / hour)? 
A) 5
B) 6
C) 7
D) 8
Correct Answer : 5 Explanation : Let Abhay's speed be X km/hr and Sameer's speed be Y km/hr Abhay doubles his speed, i.e his speed becomes 2x, then he would take 1 hour less than Sameer After adding above equations 
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The speed of Karan is 40 kmph and the speed of Arjun is 60 kmph. What is the ratio of time taken by each to cover the same distance? 
A) 3 : 2
B) 2 : 3
C) 1 : 2
D) 4:3
Correct Answer : 3: 2 Explanation : karan cover a km distance in 1/40 hour and Arjun take 1/60 hour 
A boy goes to school at the speed of 3 km per hour and returns at a speed of 2 km/hr. If he takes 5 hours in all, the distance of school is: (in km)? 
A) 6
B) 7
C) 8
D) 9
Correct Answer : 6 Explanation : let the distance is x.then 
A person can reach a place in 50 days by walking and resting for 9 hours a day. If he doubles his speed and also rests for double time then in how many days will he cover the double distance? 
A) 126
B) 128
C) 125
D) 129
Correct Answer : 125 Explanation : he walk = 24  9 = 15 hours per day let the speed is s,distance is d and time is t. he rests twice more than he did before, so he would walk = 24  (2*9) = 6 hours per day So,Required number of days = 750/6 = 125 days 
Walking at 3/4 of her normal speed Malleshwari takes 2 hours more than the normal time to reach the destination. What is her normal time? 
A) 4 hours
B) 5 hours
C) 6 hours
D) 8 hours
Correct Answer : 6 hours Explanation : Distance(d)=Speed(S)*Time(t) 
Rahul runs a distance of 1500 m in 5 minutes. What is his speed in Km/hr ? 
A) 16 km/hr
B) 18 km/hr
C) 15 km/hr
D) 20 km/hr
Correct Answer : 18 km/hr Explanation : Speed(S) = Distance(d)/Time(t) 
In how many minutes will Rohit cover a distance of 800 m, if he runs at speed of 10 km/hr? 
A) 5 min 12 sec
B) 4 min 40 sec
C) 5 min
D) 4 min 48 sec
Correct Answer : 4 min 48 sec Explanation : Speed(S) = Distance(d)/Time(t) Time taken to cover 800 m = 800 / (50/18) sec = 800 *18 / 50 sec = 288 sec = 4 min 48 sec 

Vinay cover twothird of a certain distance at 4 km/hr and the remaining at 5 km/hr. If he takes 42 minutes in all, the distance is? 
A) 2.5 km
B) 4.6 km
C) 4 km
D) 3 km
Correct Answer : 3 km Explanation : Speed(S) = Distance(d)/Time(t) 
A man goes uphill with an average speed of 35 km/hr, and covers down with an average speed of 45 km/hr. The distance travelled in both the cases being the same , the average speed for the entire journey is ? 
A) 315/8 km/hr
B) 325/8 km/hr
C) 40 km/hr
D) 315 km/hr
Correct Answer : 315/8 km/hr Explanation : When d1 = d2 , Average speed = 2*S1*S2/(S1+S2), where S1 and S2 are the speeds for covering d1 and d2 respectively Average speed = ( 2*35*45) / (35 + 45) km/hr. = 3150 / 80 = 315 / 8 km/hr 
Everyday Ramesh walks to his office at a speed of 2 km/hr and returns at a speed of 3 km/hr. If he takes 5 hours in his to and fro journey, how far is his office from his home? 
A) 12 Kms
B) 6 Kms
C) 5 Kms
D) 3 Kms
Correct Answer : 6 Kms Explanation : Let distance between his house and office be x km x/2 + x/3=5 i.e., distance between house and office = 6 km 

The ratio of the speed of two cars is 5 : 4. So, what is the ratio of their time to cover the same distance? 
A) 5 : 4
B) 6 : 4
C) 6 : 5
D) 4 : 5
Correct Answer : 4 : 5 Explanation : Speed(s) = Distance(d)/Time(t) 
To cover a distance of 315 km in 2.8 hours what should be the average speed of the car? 
A) 112.5 m/s B) 56.25 m/s C) 62.5 m/s D) 31.25 m/s Correct Answer : 31.25 m/s Explanation : Total distance = 315 km = 315000 m 
A thief is spotted by a policeman from a distacne of 100 m. When the policeman starts the chase, the thief also starts running. If the speed of the theif is 8 km / hour and that of the policeman is 10 km/hour, then how far will the theif have to run before he is overtaken? 
A) 200 m B) 300 m C) 400 m D) 500 m Correct Answer : 400 m Explanation : Let us assume that the time to taken by the policeman to catch the thief is t. Time is same for the thief and policeman. According to question, 10t = 8t + 100/1000 km Distance run by thief in 0.05 Hrs =8*0.05 km = 0.4 km = 400 m 
Starting from the same point at the same time, Ruhan and Yuvan had to reach the same destination. While Ruhan drove at 45 km/hr, Yuvan was slower by 5 km/hr. If Yuvan arrived at the destination an hour after Ruhan did, the distance covered by each, in Kilometres, was ? 
A) 180
B) 420
C) 225
D) 360
Correct Answer : 360 Explanation : Let the distance is X km , Speed= Distance/Time Time taken to travel by Ruhan = X/45 Yuvan speed = 5 km/hr slower than Ruhan= 45  5 km/hr = 40 km/hr Time taken to travel by Yuvan = X/40 As is given, X/40  X/45 = 1 (an hour) (9*X  8*X) / 360 = 1 X = 360 
While going form A to B, Rahman drove at 40 km an hour but while coming back he drove at only 24 km an hour. what was the average speed (in km/hr) at which he drove ? 
A) 30
B) 31
C) 32
D) 33
Correct Answer : 30 Explanation : When d1 = d2 , Average speed = 2S1S2/(S1+S2), where S1 and S2 are the speeds for covering d1 and d2 respectively Average speed = 2S1S2/(S1+S2) = 2*40*24/(40+24)= 30 km/hr 