# Time and Distance- Aptitude Questions and Answers

 A man goes uphill with an average speed of 35 km/hr, and covers down with an average speed of 45 km/hr. The distance travelled in both the cases being the same , the average speed for the entire journey is ? A) 315/8 km/hr B) 325/8 km/hr C) 40 km/hr D) 315 km/hr Correct Answer : 315/8 km/hr Explanation :When d1 = d2 , Average speed = 2*S1*S2/(S1+S2), where S1 and S2 are the speeds for covering d1 and d2 respectively Average speed = ( 2*35*45) / (35 + 45) km/hr. = 3150 / 80 = 315 / 8 km/hr Post/View Answer Post comment Cancel Thanks for your comment.! Write a comment(Click here) ...
 The speed of Karan is 40 kmph and the speed of Arjun is 60 kmph. What is the ratio of time taken by each to cover the same distance? A) 3 : 2 B) 2 : 3 C) 1 : 2 D) 4:3 Correct Answer : 3: 2 Explanation :karan cover a km distance in 1/40 hour and Arjun take 1/60 hour Hence ratio of time taken by karan and arjun would be 60/40 =3/2 A boy goes to school at the speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in all, the distance of school is: (in km)? A) 6 B) 7 C) 8 D) 9 Correct Answer : 6 Explanation :Let the distance is x.then Time to go to school + Time taken in return = 5 x/3 + x/2 = 5 2x+3x / 6 = 5 5x = 30 So ditance of school is , x = 6 km A person can reach a place in 50 days by walking and resting for 9 hours a day. If he doubles his speed and also rests for double time then in how many days will he cover the double distance? A) 126 B) 128 C) 125 D) 129 Correct Answer : 125 Explanation :he walk = 24 - 9 = 15 hours per day so the total time he walks would be = 15 * 50 = 750 hours let the speed is s,distance is d and time is t. t = d/s = 750 hours he doubles his speed(2*s) and will cover the double distance(2*d), then new time would still be same i.e.=2*d/2*s=d/s=750 hours he rests twice more than he did before, so he would walk = 24 - (2*9) = 6 hours per day So,Required number of days = 750/6 = 125 days Walking at 3/4 of her normal speed Malleshwari takes 2 hours more than the normal time to reach the destination. What is her normal time? A) 4 hours B) 5 hours C) 6 hours D) 8 hours Correct Answer : 6 hours Explanation :Distance(d)=Speed(S)*Time(t) Let the Speed is s and Time is t distance coverd by Malleshwari in both case is equal.then s * t = (3/4) * s *(t + 2) t = (3/4) * (t + 2) t - 3*t/4 = 3/2 t/4 = 3/2 t = 6 Rahul runs a distance of 1500 m in 5 minutes. What is his speed in Km/hr ? A) 16 km/hr B) 18 km/hr C) 15 km/hr D) 20 km/hr Correct Answer : 18 km/hr Explanation :Speed(S) = Distance(d)/Time(t) = 1500/ 5 m/mins = 300 m/mins = 300 * (60/1000 ) km/hr = 18 km/hr In how many minutes will Rohit cover a distance of 800 m, if he runs at speed of 10 km/hr? A) 5 min 12 sec B) 4 min 40 sec C) 5 min D) 4 min 48 sec Correct Answer : 4 min 48 sec Explanation :Speed(S) = Distance(d)/Time(t) Rohit's speed = 10 Km/hr = (10 * 5/18) m/sec = 50/18 m/sec Time taken to cover 800 m = 800 / (50/18) sec = 800 *18 / 50 sec = 288 sec = 4 min 48 sec Vinay cover two-third of a certain distance at 4 km/hr and the remaining at 5 km/hr. If he takes 42 minutes in all, the distance is? A) 2.5 km B) 4.6 km C) 4 km D) 3 km Correct Answer : 3 km Explanation :Speed(S) = Distance(d)/Time(t) Let total distance be d km. Then , (2d / 3) / 4 + ( d / 3) / 5 = 42/60 d/6 + d/ 15 = 7/10 5d + 2d = 21 hence, Required distance d = 3 km Everyday Ramesh walks to his office at a speed of 2 km/hr and returns at a speed of 3 km/hr. If he takes 5 hours in his to and fro journey, how far is his office from his home? A) 12 Kms B) 6 Kms C) 5 Kms D) 3 Kms Correct Answer : 6 Kms Explanation :Let distance between his house and office be x km Time taken to go to office =x/2 hr Time taken to return =x/3 hr x/2 + x/3=5 2x+3x=30 5x=30 x=6 i.e., distance between house and office = 6 km In 30 km distance, Abhay takes two hours more than Sameer. If Abhay will double his speed, then he will take less than 1 hour from Sameer. What is the speed of Abhay (in km / hour)? A) 5 B) 6 C) 7 D) 8 Correct Answer : 5 Explanation :Let Abhay's speed be X km/hr and Sameer's speed be Y km/hr As is given, Abhay takes 2 hours more than Sameer 30/X - 30/Y = 2 ........ (i) Abhay doubles his speed, i.e his speed becomes 2x, then he would take 1 hour less than Sameer 30/Y - 30/2X = 1 ......... (ii) After adding above equations 30/X - 30/2X = 3 30/2X=3 X = 5 km/h The ratio of the speed of two cars is 5 : 4. So, what is the ratio of their time to cover the same distance? A) 5 : 4 B) 6 : 4 C) 6 : 5 D) 4 : 5 Correct Answer : 4 : 5 Explanation :Speed(s) = Distance(d)/Time(t) T1 =D/5 T2=D/4 T1/T2 = 4 / 5 To cover a distance of 315 km in 2.8 hours what should be the average speed of the car? A) 112.5 m/s B) 56.25 m/s C) 62.5 m/s D) 31.25 m/s Correct Answer : 31.25 m/s Explanation :Total distance = 315 km = 315000 m Total time = 2.8 * 60 * 60 sec Average speed = Total distance/Total time = 315000/2.8 * 60 * 60 = 31.25 m/s A thief is spotted by a policeman from a distacne of 100 m. When the policeman starts the chase, the thief also starts running. If the speed of the theif is 8 km / hour and that of the policeman is 10 km/hour, then how far will the theif have to run before he is overtaken? A) 200 m B) 300 m C) 400 m D) 500 m Correct Answer : 400 m Explanation :Let us assume that the time to taken by the policeman to catch the thief is t. Now, distance run by police in time, t = t*10 Time is same for the thief and policeman. According to question, 10t = 8t + 100/1000 km 2t = 0.1 t = 0.05 Distance run by thief in 0.05 Hrs =8*0.05 km = 0.4 km = 400 m Starting from the same point at the same time, Ruhan and Yuvan had to reach the same destination. While Ruhan drove at 45 km/hr, Yuvan was slower by 5 km/hr. If Yuvan arrived at the destination an hour after Ruhan did, the distance covered by each, in Kilometres, was ? A) 180 B) 420 C) 225 D) 360 Correct Answer : 360 Explanation :Let the distance is X km , Speed= Distance/Time Time taken to travel by Ruhan = X/45 Yuvan speed = 5 km/hr slower than Ruhan= 45 - 5 km/hr = 40 km/hr Time taken to travel by Yuvan = X/40 As is given, X/40 - X/45 = 1 (an hour) (9*X - 8*X) / 360 = 1 X = 360 While going form A to B, Rahman drove at 40 km an hour but while coming back he drove at only 24 km an hour. what was the average speed (in km/hr) at which he drove ? A) 30 B) 31 C) 32 D) 33 Correct Answer : 30 Explanation :When d1 = d2 , Average speed = 2S1S2/(S1+S2), where S1 and S2 are the speeds for covering d1 and d2 respectively Average speed = 2S1S2/(S1+S2) = 2*40*24/(40+24)= 30 km/hr How many minutes does a car take to cover a distance of 200 m, if it runs at a speed of 60 kmph? A) 1/3 minutes B) 1/5 minutes C) 1/6 minutes D) 1/8 minutes Correct Answer : 1/5 minutes Explanation :Time taken to cover 60 km = 1 hour that is 60000 m = 60 minutes (1 km=1000 m,1 hour=60 minutes) Time taken to cover 1 m = 60/60000 minutes = 1/1000 minutes Time taken to cover 200 m = 200 * 1/1000 minutes = 1/5 minutes.