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There is a path made around a circular park. If the difference of external and internal perimeters is 132 meter, then the width of the path is: किसी वृत्तकार उद्यान के चारों ओर एक समान चौड़ाई का एक पथ बना हुआ है । यदि इस वृत्ताकार पथ की आंतरिक तथा बाह्य परिधियों का अंतर 132 मीटर है, तो पथ की चौड़ाई है: 
A) 22 m
B) 20 m
C) 21 m
D) 24 m
Correct Answer : 21 m Explanation : Let the inner and outer radii be r and R meters. 
The base of rightangled triangle is 5 meters and hypotenuse is 13 meters . Its area will be ? 
A) 25 m^{2}
B) 28 m^{2}
C) 30 m^{2}
D) 24 m^{2}
Correct Answer : 30 m^{2} Explanation : Hypotenuse = √(base^{2}+height^{2}) Area of the triangle = 1/2(base*height) 
If the side of a square is increased by 25%, then how much percent does its area get increased ? 
125 56.25 Explanation : Let side of square is 100 m^{2} Then, side = 10 m increased side by 25 Then, new side = 125 % of 10 ⇒ (125/100) x 10 ⇒ 12.5 m Increase in area = (12.5)^{2}  (10)^{2} m^{2} 
if the side of a square be increased by 4 cms. The area increased by 60 sq. cms . The side of the square is ? 
12 cm 5.5 cm Explanation : Let each side = x cm 

If the diameters of a circle is increased by 100% . Its area is increased by ? 
100% 300% Explanation : Area of circle = πd^{2}/4 diameters increased by 100%, then new area = π(2d)^{2} /4 => πd^{2} increase percent =[(3πd^{2}/4) / ( πd^{2}/4) ]*100 % 
Find the area of a triangle whose sides measure 8 cm, 10 cm and 12 cm? 
8√63 sq cm 5√63 sq cm Explanation : Area of triangle = √[s(sa)(sb)(sc)] there s = (a+b+c)/2 let, a = 8 cm, b = 10 cm and c = 12 cm so,Area of triangle = √s(s  a) (s  b) (s  c) 
One side of a parallelogram is 8.06 cm and its perpendicular distance from opposite side is 2.08 cm. What is the approximate area of the parallelogram? 
12.56 cm^{2} 16.76 cm^{2} Explanation : Area of parallelogram = base x height 

Find the area of a rectangle having 15m length and 8m breadth. 
120 sq m 120 sq m Explanation : Area of Rectangle= Length x Breadth 
The length of the side of a square is represented by x+2. The length of the side of an equilateral triangle is 2x. If the square and the equilateral triangle have equal perimeter, then the value of x is _______? 
A) 4 B) 5 C) 6 D) 8 Correct Answer : 4 Explanation : Since the side of the square is x + 2, its perimeter = 4 (x + 2) = 4x + 8 
The perimeters of two squares are 160cm and 164cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares(in cm). 
A) 81
B) 60
C) 36
D) 9
Correct Answer : 36 Explanation : Perimeter of Square = 4 * length of a side The perimeters of two squares are 160cm and 164cm , Area of third squre = 41^{2}  40^{2} = 81 sq cm required perimeter = 4*9 = 36 cm 
The sides of a triangle are in the ratio 3:4:5. The perimeter of the triangle is 24cm. The area (in cm^{2}) of the triangle is: 
A) 39
B) 26
C) 24
D) 32
Correct Answer : 24 Explanation : Perimeter = (a+b+c) ,there a,b,c are the sides of a triangle let's the sides of triangle are 3 cm, 4 cm, and 5 cm in length , then So Area = √[s(sa)(sb)(sc)] there s = (a+b+c)/2 = 12/2 =6 hence Area may be 6 or multiple of 6 that is 6, 12 , 24 ...because sides are given in ratio 
In a rhombus of side 10 cm, one of diagonals is 16 cm long. The length of In a rhombus of side 10 cm, one of diagonals is 16 cm long. The length of the second diagonal is ? 
A) 16 cm
B) 12 cm
C) 18 cm
D) 20 cm
Correct Answer : 12 cm Explanation : The diagonals meet in the middle at a right angle. 