# Problems on Ages- Aptitude Questions and Answers

 A father is now three times as old as his son. Five years back, he was four times as old as his son. The age of the son (in years) is? A) 12 B) 15 C) 18 D) 20 Correct Answer :15 Explanation :Let son’s age be x years. Then, father’s age = (3x) years. Five years ago, father’s age = (3x – 5) years and son’s age = (x – 5) years. As given, Five years back, father’s age was four times So, 3x – 5 = 4 (x – 5) 3x – 5 = 4x – 20 x= 15. Today is Varun’s birthday. One year, from today he will be twice as old as he was 12 years ago. How old is Varun today ? A) 20 B) 22 C) 25 D) 27 Correct Answer :25 Explanation :Let Varan’s age today = x years. Then, Varan’s age after 1 year = (x + 1) years. As given, after an year he will be twice as old as he was 12 years ago Therefore his age , x + 1 = 2 (x – 12) x + 1 = 2x – 24 x = 25. A mother is 50 years old and her son is 22 years old. The mother will be twice as old as her son after ......years ? A) 4 B) 5 C) 6 D) 8 Correct Answer :6 Explanation :Let's the after x years mother's age be twice that of his son. So (50+x)=2*(22+x) 50+x=44+2x x=6 After 6 years mother's age will be twice of his son. From today, after five years the age of father will be three times of the age of the son, while five years ago father’s age was seven times of the age of his son. Then the present ages of father and son, in years are respectively? A) 31 and 7 B) 47 and 11 C) 40 and 10 D) 30 and 11 Correct Answer :40 and 10 Explanation :Let the father's age be x and the son's age be y As it has been, after five years x + 5 = 3*(y + 5) x - 3y = 10 ....(1) And five years ago x - 5 = 7*(y - 5) x - 7y = - 30 ....(2) After solving the above equations x = 40 and y = 10 So the present age of father and son is 40 and 10 Leela got married 6 years ago.Today her age is 1(1/4) times her age at the time of her marriage. her son’s age is 1/10 times her age. What is the present age of her son? A) 1 year B) 2 years C) 3 years D) 4 years Correct Answer :3 years Explanation :Let the age of Leela at her marriage was x years. Present age of Leela = (x + 6) years As is given, x + 6 = (5/4)x 4x + 24 = 5x x = 24 Present age of Leela = x + 6 = 24 + 6 = 30 years Present age of Leela's son = (1/10)*30 = 3 years Five years ago, Somi’s age at that time was 1/3 rd of Amit’s age at that time. The respective ratio between Amit's age six years hence and Somi’s age twelve years hence, will be 7 : 4. What was Somi’s age three years ago? A) 13 yr B) 29 yr C) 17 yr D) 25 yr Correct Answer :17 yr Explanation :Let the present age of Somi = X years and present age of Amit = Y years According to the question,( X − 5) = 1/3( Y − 5 ) => 3x − 15 = Y − 5 => 3x − y = 10 …(i) and Y+6 / X+12 = 7/4 => 4Y + 24 = 7X + 84 => 4Y − 7X = 60 …(ii) Now, solving Eqs. (i) and (ii), we have X = 20 years Somi’s age three years ago = 20 − 3 = 17 years The ages of Gyanendra and Jitendra are in the ratio of 12:7 respectively. After 6 years, the ratio of their ages will be 3:2 respectively . find the difference in their ages? A) 10 years B) 24 years C) 36 years D) 48 years Correct Answer :10 years Explanation :Let,the present age of Gyanendra and Jitendra are 12x and 7x. After 6 years,the ratio of their ages, (12x+6)/(7x+6)=3/2 24x+12=21x+18 3x=6 x=2 Hence, present age of Gyanendra and Jitendra would be 24 and 14 The difference in their ages =24-14 = 10 years