Problems on Ages- Aptitude Questions and Answers

Let son’s age be x years. Then, father’s age = (3x) years.
Five years ago, father’s age = (3x – 5) years and son’s age = (x – 5) years.

As given, Five years back, father’s age was four times
So, 3x – 5 = 4 (x – 5)
3x – 5 = 4x – 20
x= 15.

Let Varan’s age today = x years.
Then, Varan’s age after 1 year = (x + 1) years.

As given, after an year he will be twice as old as he was 12 years ago
Therefore his age , x + 1 = 2 (x – 12)
x + 1 = 2x – 24
x = 25.

Let's the after x years mother's age be twice that of his son.

So (50+x)=2*(22+x)
50+x=44+2x
x=6
After 6 years mother's age will be twice of his son.

Let the father's age be x and the son's age be y

As it has been, after five years
x + 5 = 3*(y + 5)
x - 3y = 10 ....(1)

And five years ago
x - 5 = 7*(y - 5)
x - 7y = - 30 ....(2)

After solving the above equations x = 40 and y = 10
So the present age of father and son is 40 and 10

Let the age of Leela at her marriage was x years.
Present age of Leela = (x + 6) years
As is given, x + 6 = (5/4)x
4x + 24 = 5x
x = 24
Present age of Leela = x + 6 = 24 + 6 = 30 years
Present age of Leela's son = (1/10)*30 = 3 years

Let the present age of Somi = X years and present age of Amit = Y years
According to the question,( X − 5) = 1/3( Y − 5 )
=> 3x − 15 = Y − 5
=> 3x − y = 10 …(i)
and
Y+6 / X+12 = 7/4
=> 4Y + 24 = 7X + 84
=> 4Y − 7X = 60 …(ii)

Now, solving Eqs. (i) and (ii), we have X = 20 years
Somi’s age three years ago = 20 − 3 = 17 years

Let,the present age of Gyanendra and Jitendra are 12x and 7x.
After 6 years,the ratio of their ages, (12x+6)/(7x+6)=3/2
24x+12=21x+18
3x=6
x=2
Hence, present age of Gyanendra and Jitendra would be 24 and 14
The difference in their ages =24-14 = 10 years

let the present age be x
Age after 12 years=x+12
Age before 4 years=x-4

Then as given, (x+12)= 3(x-4)
x+12= 3x-12
24=3x-x
24=2x
x=12

Sum of values = Average of values * Number of values

Total age of 15 people = 45 * 15 = 675 years
Total age of remaining people after 2 person left = (45 + 5) * (15 – 2)
=50 × 13
=650 years

Total age of 2 excluded people = Total age of 15 people – Total age of remaining people after 2 person left
=675 – 650
=25 years

Average of 2 excluded people = Total age of 2 excluded people/2
=25/2
=12.5 years

Let X be age of son, A's age= 6X and A's father age= 6X+40.
As given
X + 6X + 6X+40=118
13X=118-40
X= 78/13
X= 6, then x = 36
Hence, A's age= 6X = 6*6 = 36 years

Let the ages X and Y
X-Y= 2 ....(1)

X+Y= √144
=> X+Y= 12 ....(2)

from eq (1) and (2)

X-Y= 2
X+Y= 12
------------
2X =14

X=7
by eq(1) X -Y =2
7-Y= 2
Y=5

The age of the elder is 7 years

Let x be current age of C
Then, B's age = 2x years. A's age = (2x + 2) years.

Total of their ages = x + 2x + 2x + 2 = 27
5x = 25
x = 5
C is 5 years old,
B's age = 2x = 2*5 = 10 years
A's age = (2x + 2) = (2*5+2) = 12 years

Let, Present age of father is 9x and age of son is 4x

After five years:
Age of father = 9x + 5
Age of son = 4x + 5

as is given,Sum of their ages after five years = 75
9x + 5 + 4x + 5 = 75
13x + 10 = 75
13x = 65
x = 5

Present age of father, 9x= 9 × 5 = 45 years.

Total age of 7 people, average age is 17 years = 7 * 17 = 119
Two new people joined with an average age 19 years = 19 * 2 = 38
Total age of 9 people = 119 + 38 = 157

Total age of 8 people after one person left the group = 157 - 25 = 132

New average age of the group = 132/8 = 16.5 years

Let the present age be 'x' years.
Then father's present age is 3x+3 years.
3 years later, age of son = x+3

As given, Three years later
(3x+3)+3=2(x+3)+10
3x+6=2x+16
x=10

Hence father's present age = 3x+3 = 33 years

Let us assume Ramu & Somu ages, 1 year ago, be 6x and 7x respectively.
Given that, four years hence, this ratio would become 7:8
⇒(6x+5):(7x+5)=7:8
⇒8(6x+5)=7(7x+5)
⇒48x+40=49x+35
⇒x=5
Somu's present age = 7x+1= 7×5+1=36 years