Ratio and Proportion- Aptitude Questions and Answers

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If R:S = 0.01:0.11 and S:T = 2.2:1, Find R:S:T?

A)

2:2:1


B)

20:22:10


C)

20:2:1


D)

2:22:10



Correct Answer :

2:22:10


Explanation :

R:S = 0.01:0.11 = 1:11
S:T = 2.2:1 = 22:10

Therefore for the ratio R:S:T

R:S = 1*22:11*22
S:T = 22*11:10*11

R:S:T = 1*22 : 11*22 : 10*11
=1*2:11*2:10*1
=2:22:10

In a school, Under a Saving Scheme, Rekha saves 3/2 times the savings of Bindu, Geeta saves 4 times the savings of Rekha. Find the ratio of the savings of all the three in least terms?

A)

12 : 13 : 12


B)

12 : 3 : 12


C)

2 : 3 : 4


D)

2 : 3 : 12



Correct Answer :

2 : 3 : 12


Explanation :

As is given R = 1.5B
G = 4R = 4*1.5 = 6

So ratio of the savings their saving
B : R : G = 1 : 1.5 : 6
= 1 : 3/2 : 6
= 2 : 3 : 12

The ratio of savings of Bindhu to Rekha to Geeta is 2 : 3 : 12

A certain sum of money is divided between A and B in the ratio of 5/4 : 5/3 and A got Rs. 360/-. Find the total sum of money and B’s share?

A)

480


B)

120


C)

240


D)

540



Correct Answer :

480


Explanation :

Let the share of B be X
Given ratios are

A : B = 5/4 : 5/3 = 15/20 = 3/4

Now 360/X = 3/4
So B's share, X=480
total sum of money = 360+480 = 840

In an office, the ratio of the salaries of an officer and a clerk is 15:7. If the salary of a clerk is Rs. 720/- less than the salary of the officer, find the salary of each?

A)

1000 ,600


B)

1050 ,630


C)

1250 ,60


D)

1350 ,630



Correct Answer :

1350 ,630


Explanation :

Let the salary of officer is X and clerk is Y
as is given
X/Y = 15/7 ---eq 1
X-Y = 720 ----eq 2

from eq1 X=15Y/7
and substituting it in eq2

15Y/7 - Y =720
8Y= 720*7
Hence salary of clerk is, Y = 630
and salary of officer is, X = 15Y/7 = 15*630/7 = 1350

In an election to a municipal council, the votes secured by two candidates are in the ratio 13:19. The elected candidates gets 312 votes more than the second candidate. How many votes are secured by the second candidate?

A)

500


B)

620


C)

676


D)

700



Correct Answer :

676


Explanation :

Let the two candidates are A and B
the ratio is 13:19
So,
A's votes = 13x
B's votes = 19x

As is given
19X - 13X = 312
6X = 312
X = 52
Hence A's votes= 13X = 13*52 =676
and B's votes= 19X = 19*52 = 988

the second candidate is secured 676 votes

A certain sum of money is divided between Murthy and Prasad in the ratio 22/7 : 8/3. If Murthy gets Rs. 120/- more than Prasad, find the share of each?

A)

700,600


B)

792,672


C)

892,770


D)

998,772



Correct Answer :

792,672


Explanation :

The ratio is 22/7 : 8/3 = 22*3/7*8 = 33/28
So,
Murthy's share = 33X
Prasad's share = 28X

As is given
33X - 28X = 120
5X = 120
X = 24
Hence Murthy's share = 33X = 33*24 = 792
and Prasad's share= 28X = 28*24 = 672

In a cricket test series, the runs made by Raju and Tendulkar are in the ratio 5:9 and Tendulkar and Azar are in the ratio 6:7. What are the runs made by them if Azar makes 187 runs more than Raju?

A)

110,126,250


B)

120,216,307


C)

170,306,357


D)

168,206,352



Correct Answer :

170,306,357


Explanation :

The ratio is
R/T = 5/9 = 5*6/9*6
T/A = 6/7 = 6*9/7*9

So, rotio of their runs
R:T:A = 5*6:9*6:7*9
= 5*2:9*2:7*3
= 10:18:21

As is given
21X - 10X = 187
11X = 187
X = 17

Therefore
Raju's runs= 10X = 10*17 = 170
Tendulkar's runs= 18X = 18*17 = 306
Azar's runs= 21X = 21*17 = 357

Annual incomes of the families of Sita and Latha are in the ratio 4:3 and their annual expenditure are in the ratio 3:2. What is their annual income if they save Rs. 3000/- in a year?

A)

10000,7000


B)

11000,8000


C)

12000,9000


D)

13000,10000



Correct Answer :

12000,9000


Explanation :

Let annual income of the families of Sita and Latha be 4x and 3x,
and expenditure be 3y and 2y respectively

As is given
Saving of families of Sita 4x−3y=3000 ---(1)
Saving of families of Latha 3x−2y=3000 ---(2)

After resolving eq 1 and 2
8x−6y=6000
9x−6y=9000

x=3000

Hence, Annual income of the families of Sita=4x=12000
Annual income of the families of Latha=3x=9000

The cost of 10 books is Rs. 80/-. Find the value of 15 books?

A)

90


B)
100

C)
110

D)
120


Correct Answer :

120


Explanation :

Let the cost of a book is X
As is given 10X = 80 rs
X=80/10
X=8

Hence, value of 15 books= 15*X
=15*8
=120 Rs

The cost of 48 bags of paddy is Rs. 16,800/-. What is the cost of 36 bags of paddy?

A)

12400


B)
12600

C)
12800

D)
13000


Correct Answer :

120


Explanation :

Let the cost of 36 bags is X,
Then
48 bags of paddy : 36 bags of paddy = Rs 16800 : X
X = 16800*36 / 48

Hence, the cost of 36 bags is X =12600

Monthly expenditure of a family of 4 members is Rs 2800/-. What is the expenditure if there are 3 members in the family?

A)

1900


B)
2000

C)
2100

D)
2200


Correct Answer :

2100


Explanation :

Let the expenditure of 3 members in the family is X
Then
expenditure of 4 members : expenditure of 3 members = Rs 2800 : X
X = 2800*3 / 4
X = 2100
Hence, expenditure of 3 members is, X = 2100

Find the mean proportional between 8 and 32 ?

A)

12


B)

13


C)

14


D)

16



Correct Answer :

16


Explanation :

Mean proportional between a and b is square root of ab.

Mean Proportional= √(8*32) =16

The mess charge for 35 students for 24 days is Rs. 6300/-. In how many days will the mess charges be Rs. 3375/- for 25 students?

A)

12


B)

14


C)

18


D)

22



Correct Answer :

18


Explanation :

The rate for one student per day is the same, so

35 students*24 days / 25 students* X days = 6300 Rs/3375 Rs
35*24*3375 = 6300*25*X
X = 35*24*3375 / 6300*25
X = 18

Rice costing Rs. 480/- is needed for 8 members for 20 days. What is the cost of rice required for 12 members for 15 days?

A)

540


B)

320


C)

450


D)

560



Correct Answer :

540


Explanation :

cost of rice for 8 members in a family for 20 days = 480 Rs
cost of rice for 1 members for 1 day= 480/ 8*20 = 24 Rs
Now cost of rice for 12 members for 15 days= 480*12*15 / 8*20 = 540 Rs

10 men can lay a road of 75 Km long in 5 days. In how many days can 15 men lay a road of 45 Km long?

A)

4


B)

3


C)

2


D)

1



Correct Answer :

2


Explanation :

10 men*5 days / 15 men*X days = 75 Km/45 Km
10*5*45 = 75*15*X
X = 10*5*45 / 75*15
X = 2

Therefore, 15 men can lay a road of 45 Km long in 2 days

24 men working at 8 hours a day can do a piece of work in 15 days. In how many days can 20 men working at 9 hours a day do the same work?

A)

12


B)

14


C)

16


D)

18



Correct Answer :

16


Explanation :

People* hours* days is always constant.

So let the required day be X.
24 * 8 * 15 = 20 * 9 * X
X = 24 * 8 * 15 / 20 * 9
X = 16
On solving it, 20 men working at 9 hours a day required 1616 days to complete the same work

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