Ratio and Proportion- Aptitude Questions and Answers

R:S = 0.01:0.11 = 1:11
S:T = 2.2:1 = 22:10

Therefore for the ratio R:S:T

R:S = 1*22:11*22
S:T = 22*11:10*11

R:S:T = 1*22 : 11*22 : 10*11
=1*2:11*2:10*1
=2:22:10

As is given R = 1.5B
G = 4R = 4*1.5 = 6

So ratio of the savings their saving
B : R : G = 1 : 1.5 : 6
= 1 : 3/2 : 6
= 2 : 3 : 12

The ratio of savings of Bindhu to Rekha to Geeta is 2 : 3 : 12

Let the share of B be X
Given ratios are

A : B = 5/4 : 5/3 = 15/20 = 3/4

Now 360/X = 3/4
So B's share, X=480
total sum of money = 360+480 = 840

Let the salary of officer is X and clerk is Y
as is given
X/Y = 15/7 ---eq 1
X-Y = 720 ----eq 2

from eq1 X=15Y/7
and substituting it in eq2

15Y/7 - Y =720
8Y= 720*7
Hence salary of clerk is, Y = 630
and salary of officer is, X = 15Y/7 = 15*630/7 = 1350

Let the two candidates are A and B
the ratio is 13:19
So,
A's votes = 13x
B's votes = 19x

As is given
19X - 13X = 312
6X = 312
X = 52
Hence A's votes= 13X = 13*52 =676
and B's votes= 19X = 19*52 = 988

the second candidate is secured 676 votes

The ratio is 22/7 : 8/3 = 22*3/7*8 = 33/28
So,
Murthy's share = 33X
Prasad's share = 28X

As is given
33X - 28X = 120
5X = 120
X = 24
Hence Murthy's share = 33X = 33*24 = 792
and Prasad's share= 28X = 28*24 = 672

The ratio is
R/T = 5/9 = 5*6/9*6
T/A = 6/7 = 6*9/7*9

So, rotio of their runs
R:T:A = 5*6:9*6:7*9
= 5*2:9*2:7*3
= 10:18:21

As is given
21X - 10X = 187
11X = 187
X = 17

Therefore
Raju's runs= 10X = 10*17 = 170
Tendulkar's runs= 18X = 18*17 = 306
Azar's runs= 21X = 21*17 = 357

Let annual income of the families of Sita and Latha be 4x and 3x,
and expenditure be 3y and 2y respectively

As is given
Saving of families of Sita 4x−3y=3000 ---(1)
Saving of families of Latha 3x−2y=3000 ---(2)

After resolving eq 1 and 2
8x−6y=6000
9x−6y=9000

x=3000

Hence, Annual income of the families of Sita=4x=12000
Annual income of the families of Latha=3x=9000

Let the cost of a book is X
As is given 10X = 80 rs
X=80/10
X=8

Hence, value of 15 books= 15*X
=15*8
=120 Rs

Let the cost of 36 bags is X,
Then
48 bags of paddy : 36 bags of paddy = Rs 16800 : X
X = 16800*36 / 48

Hence, the cost of 36 bags is X =12600

Let the expenditure of 3 members in the family is X
Then
expenditure of 4 members : expenditure of 3 members = Rs 2800 : X
X = 2800*3 / 4
X = 2100
Hence, expenditure of 3 members is, X = 2100

Mean proportional between a and b is square root of ab.

Mean Proportional= √(8*32) =16

The rate for one student per day is the same, so

35 students*24 days / 25 students* X days = 6300 Rs/3375 Rs
35*24*3375 = 6300*25*X
X = 35*24*3375 / 6300*25
X = 18

cost of rice for 8 members in a family for 20 days = 480 Rs
cost of rice for 1 members for 1 day= 480/ 8*20 = 24 Rs
Now cost of rice for 12 members for 15 days= 480*12*15 / 8*20 = 540 Rs

10 men*5 days / 15 men*X days = 75 Km/45 Km
10*5*45 = 75*15*X
X = 10*5*45 / 75*15
X = 2

Therefore, 15 men can lay a road of 45 Km long in 2 days

People* hours* days is always constant.

So let the required day be X.
24 * 8 * 15 = 20 * 9 * X
X = 24 * 8 * 15 / 20 * 9
X = 16
On solving it, 20 men working at 9 hours a day required 1616 days to complete the same work