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Ratio and Proportion- Aptitude Questions and Answers

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175 men can dig a canal of 3150 meters long in 36 days. How many men are required to dig a canal of 3900 meters long in 24 days?

A)

325


B)

350


C)

375


D)

400



Correct Answer :

325


Explanation :

175 men*36 days / X men*24 days = 3150 meters/3900 meters
175 *36 *3900 = 3150 *24 *X
X = 175 *36 *3900 / 3150 *24
X = 325

So, 325 men are required.

A bag contains red, blue and black balls. The ratio of red to blue balls is 3 : 5. The ratio of black to red balls is 3 : 4. What is the ratio of blue to black balls?

A)
5 : 3

B)
4 : 5

C)
9 : 20

D)
20 : 9


Correct Answer :

20 : 9


Explanation :

ratio of red to blue balls= red / blue = 3 / 5
ratio of black to red balls= black / red = 3 / 4

ratio of black to blue balls= (black / red) * (red / blue)
= (3 / 4) * (3 / 5)
= 3*3 / 4*5
= 9 / 20

Hence, ratio of blue to black balls = 1 /(9/20) = 20/9

2/7 of the stamps in Ravi's stamp collection are Indian stamps and the remaining are foreign stamps. What is the ratio of Indian stamps to foreign stamps in Ravi's stamp collection?

A)

2 : 5


B)

5 : 7


C)

5 : 2


D)

7 : 5



Correct Answer :

2 : 5


Explanation :

Total 7 stamps 2 are Indian stamps
Indian + Foreign stamps = 7
2 + Foreign stamps = 7
Foreign stamps = 5

the ratio of Indian stamps to Foreign stamps in Ravi’s collection= 2/5

A certain sum was divided among A, B and C in the ratio 5 : 7 : 6. If B received Rs 4500 more than C, find C's share?

A)

30,000


B)

27,000


C)

25,000


D)

23,000



Correct Answer :

27,000


Explanation :

Let the amount received by A, B, c be 5x, 7x and 6x respectively.
Since B received 4500 more than C,

7x-6x = 4500
x = 4500

C's share = 6x = 6*4500 = 27000
Hence, C's share is Rs 27000

Rs 750 are divided among A, B and C in such a manner that A : B = 5 : 2 and B : C = 7 : 13, What is A’s share?

A)
Rs 250

B)
Rs 300

C)
Rs 350

D)
Rs 400


Correct Answer :

Rs 350


Explanation :

Given ratio :
A : B = 5 : 2
B : C = 7 : 13

Solving for A : B : C
If A : B = a : b1 and B : C = b2 : c, then A : B : C = ab2 : b1b2 : b1c
So, A : B : C = 35 : 14 : 26
Let A, B and C be 35x, 14x and 26x respectively
35x + 14x + 26x = 750
75x = 750
x = 750/75
x = 10

A’s share, 35x = 35*10 = Rs 350
required A’s share = Rs. 350

An alloy contains copper and zinc in the ratio 5 : 3 and another contains copper and tin in the ratio 8 : 5, If equal weights of the two are melted together to form a 3​ rd​ alloy, find the weight of tin per kg in the new alloy?

A)
40/129

B)
5/13

C)
5/26

D)
28/5


Correct Answer :

5/26


Explanation :


Assume X kg of both the alloys are melted together.

weight of copper in X kg of 1st alloy = X* 5/5+3 = 5X/8 kg
weight of Zinc in X kg of 1st alloy = X* 3/5+3 = 3X/8 kg
Similarly
weight of Copper in X kg of 2nd alloy = X* 8/8+5 = 8X/13 kg
weight of Tin in X kg of 2nd alloy = X* 5/8+5 = 5X/13 kg

both alloy melted together, so total weight= X + X = 2X
Weight of tin per kg in total weight = 5X/13 kg / 2X = 5/26
Hence weight of tin in the resulting alloy per kg = 5/26

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Ratio and Proportion - Important Formulas,Tricks and Examples

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