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A sum of money doubles in 10 years. In how many years will it become four times at the same rate of simple interest? 
A) 30 years
B) 50 years
C) 20 years
D) 25 years
Correct Answer : 30 years Explanation : Let Principal = P, Rate = R% per annum, Time = n years. money doubles in 10 years then, 2P=P+(P*R*10 )/100 it become four times at the same rate then, 4P=P+(P*10*T )/100 
A principle becomes twice in 5 years. In how many years it will become 10 times? 
A) 45 years
B) 25 years
C) 50 years
D) None of these
Correct Answer : 45 years Explanation : A = P(1 + rt/100) 
If a sum becomes Rs.18300 in 15/2 years at the rate of 7% per annum, find the sum? 
A) Rs. 10000
B) Rs. 12000
C) Rs. 14000
D) Rs. 15000
Correct Answer : Rs. 12000 Explanation : Simple Interest (SI) = (P*R*T )/100 
Find the sum of money will amount to Rs 900 in 4 years at 5 % per annum on simple interest? 
A) Rs 750 B) Rs 650 C) Rs 500 D) Rs 550 Correct Answer : Rs 750 Explanation : Let Principal = P, Rate = R% per annum, Time = n years. Amount =P + (P*R*T )/100 Thus, 900 = P + (P*5*4 )/100 
At what rate percent per annum will a sum of money doubles in 8 years? 
A) 12 %
B) 12.5 %
C) 13 %
D) 15 %
Correct Answer : 12.5 % Explanation : Let Principal = P, Rate = R% per annum, Time = n years. Amount =P + (P*R*T )/100 
A sum of money amounts to Rs. 702 in 2 years and Rs. 783 in 3 years. The rate percent is ? 
A) 12% per annum
B) 13% per annum
C) 14% per annum
D) 15% per annum
Correct Answer : 15% per annum Explanation : Let Principal = P, Rate = R% per annum, Time = n years. S.I. for 1 year = Rs. (783  702) = Rs 81 

Rahul borrowed Rs. 8000 from Mr. Chobey at simple interest. After 2 years he paid Rs. 800 more than what be borrowed and thus cleared the loan. What was the rate of interest ? 
A) 6
B) 8
C) 5
D) None of these
Correct Answer : 5 Explanation : Let Principal = P, Rate = R% per annum, Time = n years. Then, Rate R = (SI x 100) / (P*T) 
Deepak invested an amount of 21250 for 6 yr. At what rate of simple interest, will he obtain the total amount of 26350 at the end of 6 yr ? 
A) 4% pa
B) 5% pa
C) 8% pa
D) 12% pa
Correct Answer : 4% pa Explanation : Let Principal = P, Rate = R% per annum, Time = n years. Then, SI = 26350  21250 = 5100 
A sum of Rs.3900 is lent out in two parts in such a way that the simple interest on one part at 10% for 5 years is equal to that on another part at 9% for 6 years. Find the sums. 
A) 1950, 1950
B) 2025, 1875
C) 1800, 2100
D) 1950, 1800
Correct Answer : 2025, 1875 Explanation : Let Principal = P, Rate = R% per annum, Time = n years. Let, Principle lent out in two parts as x and 3900x x * 10* 5= (3900x) * 9 * 6 other part is x=2025 

The sum which amounts to Rs.889 in 3 years at the rate of 9% per annum simple interest is Rs._____? 
A) 700
B) 800
C) 600
D) 160
Correct Answer : 700 Explanation : Simple Interest (SI) = (P*R*T )/100 
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B? 
A) 7000
B) 6500
C) 6400
D) 6000
Correct Answer : 6400 Explanation : Let the sum invested in Scheme A be Rs. x , And that in Scheme B be Rs. (13900  x). 
Two equal amount were lent on simple interest of 7% and 5% respectively. The interest earned on both of them adds 960 rupees in 4 years. What is the total amount lent out? 
A) 3500
B) 2500
C) 2000
D) 3000
Correct Answer : 2000 Explanation : Let the amount is X As is given, (X*7*4 / 100) + (X*5*4 / 100) =960 
In what time will rupees 1860 amount to rupees 2641.20 at simple interest of 12%per annum? 
A) 3 years
B) 7/2 years
C) 4 years
D) 9/2 years
Correct Answer : 7/2 years Explanation : SI = 2641.20  1860 = 781.20 781.20 = (1860* 12* time) / 100 
John has invested amount at 10% per annual on simple interest. Four years later, the amount goes up to 770 rupees with interest, accordingly what was the amount? 
A) 650
B) 350
C) 550
D) 500
Correct Answer : 550 Explanation : Let the amount is X Then, after 4 years SI =770  X (770  X) = (X* 10* 4) / 100 
Ravi invested amount P in a scheme A offering simple interest at 10% per annum for two years. He invested the whole amount he received from scheme A, in another scheme B offering simple interest at 12% per annum for five years. If the difference between the interests earned from schemes A and B was 1300, what is the value of P? 
A) 2500 B) 2000 C) 3000 D) 3500 Correct Answer : 2500 Explanation : SI from scheme A = P*10*2 /100 =P/5 According to the question, 18P/25  P/5 = 1300 
A sum of money was invested at a certain rate of simple interest for 4 years. Had the sum been invested at a rate 3% higher than the actual rate, the interest earned would have been 720 Rs more. Find the sum initially invested? 
A) 24000
B) 18000
C) 6000
D) 5400
Correct Answer : 6000 Explanation : Let the sum is p , rate r and time t , then simple interest = p*r*t /100 p*4*(r+3  r) = 720*100 p*12 = 72000 p= 6000 