Time and Distance- Aptitude Questions and Answers - in Hindi

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The speed of Karan is 40 kmph and the speed of Arjun is 60 kmph. What is the ratio of time taken by each to cover the same distance?


करण की गति 40 किमी प्रति घंटा और अर्जुन की गति 60 किमी प्रति घंटा है। प्रत्येक द्वारा समान दूरी तय करने के लिए समय का अनुपात क्या होगा?

A)
3 : 2

B)
2 : 3

C)
1 : 2

D)
4:3


Correct Answer :

3: 2


Explanation :

karan cover a km distance in 1/40 hour and Arjun take 1/60 hour
Hence ratio of time taken by karan and arjun would be 60/40 =3/2

A boy goes to school at the speed of 3 km per hour and returns at a speed of 2 km/hr. If he takes 5 hours in all, the distance of school is: (in km)?


एक लड़का 3 कि. मी. प्रति घंटे की गति से स्‍कूल जाता है और 2 कि. मी. प्रति घंटे की गति से वापस आता है, यदि उसे कुल 5 घंटे लगते है तो स्‍कूल की दूरी है: (कि. मी. में)?

A)
6

B)
7

C)
8

D)
9


Correct Answer :

6


Explanation :

let the distance is x.then
x/3 + x/2 = 5
2x+3x / 6 = 5
5x = 30
So ditance of school is , x = 6 km

A person can reach a place in 50 days by walking and resting for 9 hours a day. If he doubles his speed and also rests for double time then in how many days will he cover the double distance?


एक आदमी 9 घंटे प्रतिदिन विश्राम करके एक स्थान पर पैदल 50 दिन में पहुँच सकता है । यदि वह अपनी गति को दोगुना कर दे और विश्राम भी दोगुना करे तो दोगुनी दूरी कितने दिनों में तय करेगा?

A)
126

B)
128

C)
125

D)
129


Correct Answer :

125


Explanation :

he walk = 24 - 9 = 15 hours per day
so the total time he walks would be = 15 * 50 = 750 hours

let the speed is s,distance is d and time is t.
t = d/s = 750 hours
he doubles his speed(2*s) and will cover the double distance(2*d), then new time would still be same i.e.=2*d/2*s=d/s=750 hours

he rests twice more than he did before, so he would walk = 24 - (2*9) = 6 hours per day

So,Required number of days = 750/6 = 125 days

Walking at 3/4 of her normal speed Malleshwari takes 2 hours more than the normal time to reach the destination. What is her normal time?


अपनी सामान्य चाल की 3/4 चाल से चलते हुए मल्लेश्वरी अपने गंतव्य तक पहुँचने में सामान्य समय से दो घंटा अधिक लेती है , तो उसका सामान्य समय क्या है ?

A)
4 hours

B)
5 hours

C)
6 hours

D)
8 hours


Correct Answer :

6 hours


Explanation :

Distance(d)=Speed(S)*Time(t)
Let the Speed is s and Time is t

distance coverd by Malleshwari in both case is equal.then
s * t = (3/4) * s *(t + 2)
t = (3/4) * (t + 2)
t - 3*t/4 = 3/2
t/4 = 3/2
t = 6

Rahul runs a distance of 1500 m in 5 minutes. What is his speed in Km/hr ?


राहुल 5 मिनट में 1500 मीटर की दूरी तय करता हें।तो किमी / घंटा में उसकी गति क्या है?

A)
16 km/hr

B)
18 km/hr

C)
15 km/hr

D)
20 km/hr


Correct Answer :

18 km/hr


Explanation :

Speed(S) = Distance(d)/Time(t)
= 1500/ 5 m/mins
= 300 m/mins
= 300 * (60/1000 ) km/hr
= 18 km/hr

In how many minutes will Rohit cover a distance of 800 m, if he runs at speed of 10 km/hr?


यदि रोहित 10 किमी / घंटा की गति से दौड़ता है तो वह 800 मीटर की दूरी कितने मिनट में तय करेगा?

A)
5 min 12 sec

B)
4 min 40 sec

C)
5 min

D)
4 min 48 sec


Correct Answer :

4 min 48 sec


Explanation :

Speed(S) = Distance(d)/Time(t)
Rohit's speed = 10 Km/hr = (10 * 5/18) m/sec = 50/18 m/sec

Time taken to cover 800 m = 800 / (50/18) sec = 800 *18 / 50 sec = 288 sec = 4 min 48 sec

Vinay cover two-third of a certain distance at 4 km/hr and the remaining at 5 km/hr. If he takes 42 minutes in all, the distance is?


विनय एक निश्चित दूरी के दो-तिहाई हिस्से को 4 किमी / घंटा और शेष दूरी को 5 किमी / घंटा में तय करता है। यदि वह दूरी तय करने में 42 मिनट लेता है, तो दूरी क्या है?

A)
2.5 km

B)
4.6 km

C)
4 km

D)
3 km


Correct Answer :

3 km


Explanation :

Speed(S) = Distance(d)/Time(t)
Let total distance be d km.
Then , (2d / 3) / 4 + ( d / 3) / 5 = 42/60
d/6 + d/ 15 = 7/10
5d + 2d = 21
hence, Required distance d = 3 km

A man goes uphill with an average speed of 35 km/hr, and covers down with an average speed of 45 km/hr. The distance travelled in both the cases being the same , the average speed for the entire journey is ?


एक आदमी 35 किमी / घंटा की औसत गति के साथ ऊपर की ओर जाता है, और 45 किमी / घंटा की औसत गति के साथ नीचे आता है। दोनों मामलों में, समान दूरी तय करता हैं, पूरी यात्रा की औसत गति क्या है?

A)
315/8 km/hr

B)
325/8 km/hr

C)
40 km/hr

D)
315 km/hr


Correct Answer :

315/8 km/hr


Explanation :

When d1 = d2 , Average speed = 2*S1*S2/(S1+S2), where S1 and S2 are the speeds for covering d1 and d2 respectively

Average speed = ( 2*35*45) / (35 + 45) km/hr. = 3150 / 80 = 315 / 8 km/hr

Everyday Ramesh walks to his office at a speed of 2 km/hr and returns at a speed of 3 km/hr. If he takes 5 hours in his to and fro journey, how far is his office from his home?


हर रोज रमेश 2 किमी / घंटा की रफ्तार से चलते हुए अपने कार्यालय जाता है और 3 किमी / घंटा की गति से लौटता है। अगर उसे यात्रा करने के लिए 5 घंटे लगते हैं, तो उसका घर से कार्यालय से कितना दूर है।

A)
12 Kms

B)
6 Kms

C)
5 Kms

D)
3 Kms


Correct Answer :

6 Kms


Explanation :

Let distance between his house and office be x km
Time taken to go to office =x/2 hr
Time taken to return =x/3 hr

x/2 + x/3=5
2x+3x=30
5x=30
x=6

i.e., distance between house and office = 6 km

In 30 km distance, Abhay takes two hours more than Sameer. If Abhay will double his speed, then he will take less than 1 hour from Sameer. What is the speed of Abhay (in km / hour)?


30 किमी की दूरी चलने में अभय को समीर से 2 घंटे अधिक लगते हैं। यदि अभय अपनी चाल दोगुनी कर दे, तो उसे समीर से 1 घंटे कम लगेगा। अभय कि चाल (किमी/घंटे में) है?

A)
5

B)
6

C)
7

D)
8


Correct Answer :

5


Explanation :

Let Abhay's speed be X km/hr and Sameer's speed be Y km/hr
As is given, Abhay takes 2 hours more than Sameer
30/X - 30/Y = 2 ........ (i)

Abhay doubles his speed, i.e his speed becomes 2x, then he would take 1 hour less than Sameer
30/Y - 30/2X = 1 ......... (ii)

After adding above equations
30/X - 30/2X = 3
30/2X=3
X = 5 km/h

The ratio of the speed of two cars is 5 : 4. So, what is the ratio of their time to cover the same distance?


दो कारों की गति का अनुपात 5 : 4 है। तो समान दूरी तक जाने में लगने वाले हैं उनके समय का अनुपात कितना होगा?

A)
5 : 4

B)
6 : 4

C)
6 : 5

D)
4 : 5


Correct Answer :

4 : 5


Explanation :

Speed(s) = Distance(d)/Time(t)
T1 =D/5
T2=D/4
T1/T2 = 4 / 5

To cover a distance of 315 km in 2.8 hours what should be the average speed of the car?


2.8 घंटे में 315 किमी की दूरी तय करने के लिए, कार की औसत गति कितनी होनी चाहिए?

A)

112.5 m/s


B)

56.25 m/s


C)

62.5 m/s


D)

31.25 m/s



Correct Answer :

31.25 m/s


Explanation :

Total distance = 315 km = 315000 m
Total time = 2.8 * 60 * 60 sec
Average speed = Total distance/Total time
= 315000/2.8 * 60 * 60
= 31.25 m/s

A thief is spotted by a policeman from a distacne of 100 m. When the policeman starts the chase, the thief also starts running. If the speed of the theif is 8 km / hour and that of the policeman is 10 km/hour, then how far will the theif have to run before he is overtaken?


एक पुलिसकर्मी ने एक चोर को 100 मीटर की दूरी से देखा। जब पुलिसकर्मी पीछा शुरू करता है, तो चोर भी भागने लगता है। यदि चोर की गति 8 किमी / घंटा है और पुलिसकर्मी की गति 10 किमी / घंटा है, तो पकडे जाने से पहले चोर कितनी दूर भागा होगा?

A)

200 m


B)

300 m


C)

400 m


D)

500 m



Correct Answer :

400 m


Explanation :

Let us assume that the time to taken by the policeman to catch the thief is t.
Now, distance run by police in time, t = t*10

Time is same for the thief and policeman.

According to question, 10t = 8t + 100/1000 km
2t = 0.1
t = 0.05

Distance run by thief in 0.05 Hrs =8*0.05 km = 0.4 km = 400 m

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